Calculate the enthalpy change for the reaction. Show your work.
A2 + 3B2 --> 2AB3
bond: Enthalpy:
A-A 945
A-B 390
B-B 435
To calculate the enthalpy change for the reaction, we need to use the bond enthalpies of the bonds broken and formed during the reaction. The equation for the enthalpy change is:
ΔH = Σ(bond enthalpies of bonds broken) - Σ(bond enthalpies of bonds formed)
In this reaction, we are breaking two A-B bonds and six B-B bonds, and forming four AB3 bonds. Using the given bond enthalpies, we can calculate the enthalpy change:
ΔH = [2(A-B) + 6(B-B)] - 4(AB3)
ΔH = [2(390) + 6(435)] - 4(0)
ΔH = 780 + 2610
ΔH = 3390 kJ/mol
Therefore, the enthalpy change for the reaction is 3390 kJ/mol.