Calculate the enthalpy change for the reaction. Show your work.
A2 + 3B2 --> 2AB3
To calculate the enthalpy change for the given reaction, we need to use the bond enthalpies of the reactants and products. The bond enthalpy is the energy required to break one mole of a particular bond in a gaseous molecule.
The balanced chemical equation for the reaction is:
A2 + 3B2 --> 2AB3
The bond enthalpies for the bonds involved in the reaction are:
A-A = 156 kJ/mol
B-B = 240 kJ/mol
A-B = 200 kJ/mol
The enthalpy change for the reaction can be calculated using the following equation:
ΔH = Σ (bond enthalpies of bonds broken) - Σ (bond enthalpies of bonds formed)
ΔH = [2(A-A) + 6(B-B)] - [6(A-B)]
ΔH = [2(156) + 6(240)] - [6(200)]
ΔH = 312 + 1440 - 1200
ΔH = 552 kJ/mol
Therefore, the enthalpy change for the given reaction is 552 kJ/mol.