A slide 4.1 meters long makes an angle of 35° with the ground. To the nearest tenth of a meter how far above the ground is the top of the slide.
Help please ASAP
We can use trigonometry to solve this problem.
Let's call the height we're trying to find "h".
We know that the length of the slide (the hypotenuse) is 4.1 meters and the angle it makes with the ground is 35°.
Using the trigonometric function sine, we can set up the following equation:
sin(35°) = h/4.1
To solve for h, we can multiply both sides by 4.1:
h = 4.1 * sin(35°)
Using a calculator, we get:
h ≈ 2.4 meters
Therefore, the top of the slide is about 2.4 meters above the ground.
To approach the runway, a small plane must begin a 9°
descent starting from a height of 1536 feet above the ground. To the nearest tenth, what is the horizontal distance the airplane is at the start of this approach? (hint: there are 5,280 feet in a mile) ignore the X on the diagram. You must convert feet to miles.