Question 5 of 5
If the area of parallelogram ABCD = 246 mm2 and h = 20.5 mm, what is the length of the base of triangle ABD?
We can use the formula for the area of a parallelogram, which is:
Area = base x height
In this case, the height is given as h = 20.5 mm, and the area is given as 246 mm2. We can rearrange the formula to solve for the base:
base = Area / height
Substituting the given values, we get:
base = 246 mm2 / 20.5 mm
Simplifying, we get:
base = 12 mm
Therefore, the length of the base of triangle ABD is 12 mm.
To find the length of the base of triangle ABD, we need to determine the height of the parallelogram ABCD first. Fortunately, the height (h) of the parallelogram is given as 20.5 mm.
The formula for calculating the area of a parallelogram is A = base × height, where A represents the area.
In this case, the area of the parallelogram is 246 mm^2 and the height is 20.5 mm. We can rearrange the formula to solve for the base as follows:
base = A / h
base = 246 mm^2 / 20.5 mm
base ≈ 12 mm
Therefore, the length of the base of triangle ABD is approximately 12 mm.
To find the length of the base of triangle ABD, you need to use the formula for the area of a parallelogram. The formula for the area of a parallelogram is given by:
Area = base * height
In this case, the area of parallelogram ABCD is given as 246 mm^2 and the height (h) is given as 20.5 mm.
So we can substitute these values into the formula:
246 = base * 20.5
To find the length of the base, divide both sides of the equation by 20.5:
base = 246 / 20.5
Simplifying:
base = 12 mm
Therefore, the length of the base of triangle ABD is 12 mm.