P(t)=1000/1+9e-0.7t'
What will be the fish population P after 2 years?
To find the fish population after 2 years, we need to substitute t=2 in the given logistic growth model equation:
P(2) = 1000 / (1 + 9e^(-0.7*2))
P(2) = 1000 / (1 + 9e^(-1.4))
P(2) = 1000 / (1 + 9*0.2466) [using e^(-1.4) = 0.2466]
P(2) = 1000 / (1 + 2.2194)
P(2) = 1000 / 3.2194
P(2) ≈ 310.2
Therefore, the fish population after 2 years is approximately 310.2.