22-23 Geom B Unit 4 Portfolio, im really struggling and the videos dont help, its already overdue, can anyone walk me through the problems or even better walk me through to the awnser please? ^^
Right idea by the bot, but wrong execution
the side opposite angle A has length 10
so
10^2 = 8^2 + 12^2 - 2(8)(12)cosA
cosA = 108/192
angle A = appr 55.8°
On top of that, the bot made an error in its arithmetic.
"144 = 64 + 100 - 160cos(A)"
should have given it
160cosA = 20
Problem 1:
Given: Triangle ABC with AB = 8, BC = 10, and AC = 12
Find: The measure of angle A
Solution:
We can use the Law of Cosines to solve for angle A.
The Law of Cosines states that:
c^2 = a^2 + b^2 - 2abcos(C)
Where c is the longest side of the triangle, a and b are the other two sides, and C is the angle opposite side c.
In this case, c = 12, a = 8, and b = 10.
So, we have:
12^2 = 8^2 + 10^2 - 2(8)(10)cos(A)
144 = 64 + 100 - 160cos(A)
80 = 160cos(A)
cos(A) = 0.5
Now, we can use the inverse cosine function to find the measure of angle A.
A = cos^-1(0.5)
A = 60°