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A force of 0.8N stretches an elastic spring by 2cm, find the elastic constant of the spring

Elastic constant = 0.8N/2cm = 0.4N/cm

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The elastic constant of a spring is a measure of its stiffness or how much it resists being stretched or compressed. In the given scenario, a force of 0.8N stretches an elastic spring by 2cm. By using Hooke's Law, which states that the force applied to a spring is directly proportional to the extension or compression of the spring, we can calculate the elastic constant. Dividing the force of 0.8N by the extension of 2cm (0.02m), we find that the elastic constant of the spring is 40 N/m. This means that for every meter the spring is stretched or compressed, a force of 40N is required. Understanding the concept of elastic constants helps in various fields, such as engineering, where springs are used in various applications, including shock absorbers and suspension systems.