Which of the following points are more than 5 vertical units away from the point (0, -2)
A. (0, 3)
B. (0, 8)
C. (3, -2)
B. (0, 8)
To determine which points are more than 5 vertical units away from the point (0, -2), we need to consider the y-coordinate of each point.
Let's assume we have a list of points. For each point (x, y), we can calculate the vertical distance from (0, -2) by taking the absolute value of the difference between the y-coordinate of the point and -2. If this vertical distance is greater than 5, then the point is more than 5 vertical units away from (0, -2).
Let's consider the points:
A: (-3, -8)
B: (4, -1)
C: (6, -9)
D: (2, 1)
E: (-7, -8)
For point A: Absolute value of y-coordinate difference = |-8 - (-2)| = 6, which is greater than 5. So, A is more than 5 vertical units away from (0, -2).
For point B: Absolute value of y-coordinate difference = |-1 - (-2)| = 1, which is not greater than 5. So, B is not more than 5 vertical units away from (0, -2).
For point C: Absolute value of y-coordinate difference = |-9 - (-2)| = 7, which is greater than 5. So, C is more than 5 vertical units away from (0, -2).
For point D: Absolute value of y-coordinate difference = |1 - (-2)| = 3, which is not greater than 5. So, D is not more than 5 vertical units away from (0, -2).
For point E: Absolute value of y-coordinate difference = |-8 - (-2)| = 6, which is greater than 5. So, E is more than 5 vertical units away from (0, -2).
Therefore, the points that are more than 5 vertical units away from (0, -2) are A, C, and E.