The first term of a linear sequence is 5 and the common difference is -3 find the 15th term of sequence
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AAAaannndd the bot gets it wrong yet again!
5 + 14(-3) = ___
To find the 15th term of a linear sequence, we can use the formula for the nth term of an arithmetic sequence:
\(a_n = a_1 + (n-1)d\)
where \(a_n\) represents the nth term, \(a_1\) is the first term, \(n\) is the position of the term, and \(d\) is the common difference.
Given that the first term (\(a_1\)) is 5 and the common difference (\(d\)) is -3, we can substitute these values into the formula to find the 15th term:
\(a_{15} = 5 + (15 - 1)(-3)\)
Simplifying this expression:
\(a_{15} = 5 + 14(-3)\)
\(a_{15} = 5 - 42\)
\(a_{15} = -37\)
Therefore, the 15th term of the sequence is -37.
To find the 15th term of the linear sequence, we need to use the formula for the nth term of a linear sequence, which is given by:
an = a1 + (n - 1)d
Where:
an represents the nth term of the sequence
a1 represents the first term of the sequence
d represents the common difference
In this case, we are given that the first term (a1) is 5 and the common difference (d) is -3. We are asked to find the 15th term (an).
Let's substitute these values into the formula:
a15 = 5 + (15 - 1)(-3)
Now, we can simplify the equation:
a15 = 5 + 14(-3)
a15 = 5 - 42
a15 = -37
So, the 15th term of the sequence is -37.