How do I solve a spherical triangle when 2 sides and the enclosed angle are known. Thanks Mike
AAAaannndd the bot gets it wrong yet again!
things are different in spherical trig, since all parts of a triangle are angles.
If you know A,b,c then the law of cosines becomes
cosa = cosb cosc + sinb sinc cosA
Thank you but still need more help. Would appreciate it if you would stick with me until I understand it.
One of my main issues is I do not understand how to use the formula to input the figures into a scientific calculator. I have no doubt that the formula provided is correct but I need instruction regarding its application.
Perhaps we could work an example........
Side a = 63 degrees 42 minutes
Side b = 110 degrees 27 minutes
Enclosed angle C = 94 degrees 21 minutes
Find side c
I would be most grateful for your continued support.
Mike
Thanks OOBLECK.
You will realise we were typing our replies simultaneously. My reply refers to the original reply from the BOT.
However my comments regarding not understanding the formula and how to input the info into a calculator are the same. I have to say I have come across the formula previously but what I really need is instruction in its application.
Look forward to your reply
Mike
To solve a spherical triangle when two sides and the enclosed angle are known, you can use the Law of Cosines. The Law of Cosines states that for a triangle with sides a, b, and c and angles A, B, and C, the following equation holds:
c^2 = a^2 + b^2 - 2abcos(C)
In this case, you know two sides (a and b) and the enclosed angle (C). You can use the Law of Cosines to solve for the third side (c).