A cool water sample absorbed 1,710 J of

Question

A cool water sample absorbed 1,710 J of

energy from some metal. The
temperature of the 59.0 g piece of metal
changed from 99.5 °C to 27.8 °C. What
is the specific heat of the metal?
9H₂0 1,710 J
=
J
Cmetal = [?]
[?] g. ºC
remember q,metal = -q,H₂O

Answer 1

A cool water sample absorbed 1,710 J of

Cmetal = (1,710 J) / (59.0 g)(72.7 °C) = 3.14 J/g°C