A projectile is fired at an angle such that the vertical component of its velocity and the horizontal component of its velocity are both equal to 50 m/s
A. Using g = 10 m/s^2, how long does it take for the projectile to reach its high point?
b. What horizontal distance does the projectile travel in this time?
A. The time it takes for the projectile to reach its high point is 5 seconds.
B. The horizontal distance the projectile travels in this time is 250 meters.
Vertical problem:
v = 50 - g t
if g = 9.81
v = 50 - 9.81 t
v = 0 at top
so
t = 50/9.81 = 5.1 seconds to top
Horizontal problem
horizontal distance during that five second rise = 50 * 5.1 = 255 meters
I bet they really want the horizontal distance for the whole time aloft though:
t = 10.2 seconds in the air (fall time = rise time)
u = 50 * 10.2 = 510 meters