Find the tangent line at f(x)=−1x3−1x2−4 at x=−1
Oh my, what a distaster of an answer !
Looks like Calculus is too much for the bot
f '(x) = -3x^2 - 2x
f '(-1) = -3 + 2 = -1
f(-1) = -(-1)^3 - (-1)^2 - 4
= 1 - 1 - 4 = -4
so we have a slope of -1 and a point (-1,-4)
equation of tangent:
y + 4 = -(x + 1)
y + 4 = -x - 1
y = -x - 5