an analog input signal x(t) = 1.5 +0.5 sin(100t) is sampled with 2 kHz sampling frequency fs. Assuming that sampling starts at t = 0 compute the value of the sample x[20]. Show your work.

x[20] = 1.5 + 0.5sin(100*20/2000)

= 1.5 + 0.5sin(1)
= 1.5 + 0.5(0.841471)
= 2.341471