The dry air rate is 10°C for every 1000 meters of change in elevation. What is temperature of dry air at 2500 meters if the initial temperature of air at ground level is 30°C?
AAAaannndd the bot gets it wrong yet again!
10°C for every 1000m is the same as 1°C for every 100m
so, 30° - 25° = 5°C
Thank you Oobleck!
To find the temperature of dry air at 2500 meters, we need to calculate the change in temperature based on the elevation difference and the dry air rate.
Given:
Initial temperature at ground level (elevation = 0): 30°C
Dry air rate: 10°C/1000 meters
Step 1: Find the elevation difference.
The elevation difference between ground level (0 meters) and 2500 meters is:
2500 meters - 0 meters = 2500 meters
Step 2: Calculate the change in temperature.
Using the dry air rate, we know that for every 1000 meters of change in elevation, the temperature decreases by 10°C.
So, for an elevation difference of 2500 meters:
Change in temperature = (elevation difference / 1000 meters) * (dry air rate)
Change in temperature = (2500 meters / 1000 meters) * (10°C / 1000 meters)
Change in temperature = 25 * 0.01°C
Change in temperature = 0.25°C
Step 3: Find the final temperature.
To get the final temperature, we subtract the change in temperature from the initial temperature at ground level.
Final temperature = Initial temperature - Change in temperature
Final temperature = 30°C - 0.25°C
Final temperature = 29.75°C
Therefore, the temperature of dry air at 2500 meters would be approximately 29.75°C.