physics

A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

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  1. F=ma

    a=F/m

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    bobpursley
  2. the answer is 2500

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  3. the answer is 98

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  4. A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

    and the answer is 2500

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  5. since acceleration = Net force/ mass,
    plug in 25 N for force and 100 kg for mass

    you will get 0.25 m/s^2

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  6. actually, 0.25 with sig figs is 0.3 m/s^2, which is the correct answer.

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  7. i dont understand how this is to help me??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

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  8. It would definitely be 0.25 m/s, because you are finding the deceleration which is really another way to say something accelerates, and of something is accelerating we use the formula A=f/m. Divide 25 by 100 and you get 0.25

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