# physics

A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

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1. F=ma

a=F/m

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👤
bobpursley

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4. A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

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5. since acceleration = Net force/ mass,
plug in 25 N for force and 100 kg for mass

you will get 0.25 m/s^2

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6. actually, 0.25 with sig figs is 0.3 m/s^2, which is the correct answer.

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7. i dont understand how this is to help me??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

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8. It would definitely be 0.25 m/s, because you are finding the deceleration which is really another way to say something accelerates, and of something is accelerating we use the formula A=f/m. Divide 25 by 100 and you get 0.25

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