Given that 6.10g of a metal relative atomic mass (27)react completely with 22.9g of chloride (relative atomic mass 35.5g)to give 29.0g of metalic chloride,what is the imperial formula of chloride
The formula for chloride is Cl2.
To find the empirical formula of the chloride compound, we need to determine the ratio of atoms between the metal and chlorine.
1. Convert the grams of each element to moles.
For the metal:
moles of metal = mass of metal / atomic mass of metal
moles of metal = 6.10g / 27g/mol ≈ 0.2260 mol
For chlorine:
moles of chlorine = mass of chlorine / atomic mass of chlorine
moles of chlorine = 22.9g / 35.5g/mol ≈ 0.6451 mol
2. Divide the moles of each element by the smallest number of moles to get the simplest ratio.
Dividing both values by 0.2260 mol, we get:
metal: chlorine ≈ 1 : 2.86
Since we want whole numbers, multiply the ratio by 2:
metal: chlorine ≈ 2 : 5.72
Round off to the nearest whole number:
metal: chlorine = 2 : 6
3. Write the empirical formula.
The empirical formula of the chloride compound is Cl2Mg3 (chlorine and magnesium).
To determine the empirical formula of a compound, we need to find the ratio of the elements in the compound using the given masses.
First, let's find the moles of each element in the reaction.
Moles of metal = mass of metal / molar mass of metal
Moles of metal = 6.10g / 27g/mol = 0.226 mol
Moles of chloride = mass of chloride / molar mass of chloride
Moles of chloride = 22.9g / 35.5g/mol = 0.646 mol
Next, we need to determine the ratio between the two elements in the compound. We can do this by dividing the number of moles of each element by the smaller number of moles:
Moles ratio = Moles of metal / Moles of chloride
Moles ratio = 0.226 mol / 0.226 mol = 1
Since the ratio is 1:1, the empirical formula of the chloride is just the symbol for the metal combined with the symbol for chloride, which is "MCl".