Define genotypes in phonotypes quick check in pea plants the hourly for purple flowers pee is dominant over the ollie of white flowers pee which conclusion about photon and Jennifer
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Genotypes are the genetic makeup of an organism, while phenotypes are the physical characteristics of an organism. In pea plants, the genotype for purple flowers (P) is dominant over the genotype for white flowers (p). This means that if a pea plant has a genotype of PP or Pp, it will have purple flowers, while if it has a genotype of pp, it will have white flowers. The conclusion that can be made from this is that the phenotype (the physical appearance) of the pea plant is determined by its genotype.
Typically, 10% of students make a D on their tests, 60% make a C on their tests, and 30% make an A. Mrs. Smith uses a random-number table to find the experimental probability that of 5 students’, at least 3 will make a C. The digit 0 represents students who make a D. The digits 1, 2, 3, 4, 5, and 6 represent students who make a C. The digits 7, 8, and 9 represent students who make an A.
Find the experimental probability that of 5 students at least 3 will make a C.
To find the experimental probability, we need to consider all the possible combinations of 5 students and count the ones that meet the condition of at least 3 making a C.
There are a total of 10 possible digits (0-9) that each student can represent. Therefore, there are 10^5 = 100,000 possible combinations of 5 students.
To count the number of combinations where at least 3 students make a C, we can use the binomial probability formula:
P(x ≥ 3) = 1 - P(x < 3)
where x is the number of students who make a C and P(x < 3) is the probability that less than 3 students make a C.
P(x < 3) = P(x = 0) + P(x = 1) + P(x = 2)
To find these individual probabilities, we can use the binomial probability formula again:
P(x) = (nCx) * p^x * (1-p)^(n-x)
where n is the total number of trials (5 students), x is the number of successes (C grades), p is the probability of success (0.60 for C grades), and (1-p) is the probability of failure (0.40 for not getting a C grade).
P(x = 0) = (5C0) * (0.10)^0 * (0.90)^5 = 0.59
P(x = 1) = (5C1) * (0.60)^1 * (0.40)^4 = 0.35
P(x = 2) = (5C2) * (0.60)^2 * (0.40)^3 = 0.06
Therefore, P(x < 3) = 0.59 + 0.35 + 0.06 = 1.00.
Finally, the experimental probability that at least 3 students out of 5 make a C is:
P(x ≥ 3) = 1 - P(x < 3) = 1 - 1.00 = 0.
This means that it is impossible to have at least 3 students out of 5 making a C if the probabilities of grades are as given.