Consider a particle with mass m, described by the following potential:

V (x) = ∞ for x ≤ 0
A for 0 < x < a
B for x ≥ a
Discuss the possibility of bound states for such a potential.
(a) Provide the energy of the two lowest energy states for the case B = ∞. (The prefactor is either known or needs to be derived.)
(b) How many bound states do you expect for A > B?
(c) For the case A < B provide the general solutions for the wave function in the two relevant regions and discuss the boundary conditions.
(d) Discuss the required steps to decide whether the case A < B yields a bound state. (An exact formulation of the equations is possible, but not required.)

To determine the possibility of bound states for the given potential, we need to consider the values of A and B. Let's discuss each part of the question step by step.

(a) For the case B = ∞, the potential is a step potential with a barrier at x = a. Since B is infinite, the particle cannot penetrate the barrier and will be confined to the region between 0 and a. To find the energy of the two lowest energy states in this case, we need to solve the time-independent Schrödinger equation for the region 0 < x < a.

The Schrödinger equation is:
-ħ²/2m * d²Ψ/dx² + V(x)Ψ = EΨ,

Where:
- ħ is the reduced Planck's constant,
- m is the particle's mass,
- Ψ is the wave function,
- V(x) is the potential,
- E is the energy of the particle.

Inside the potential region (0 < x < a), the potential V(x) is constant and equal to A. Thus, the Schrödinger equation becomes:
-ħ²/2m * d²Ψ/dx² + AΨ = EΨ,

Simplifying the equation, we get:
d²Ψ/dx² = -(2m/ħ²)(E - A)Ψ.

This is a second-order differential equation. Solving it will yield solutions for the wave function Ψ and energy levels E. The boundary conditions will depend on specific constraints given in the problem.

(b) For A > B, the potential barrier at x = a is lower than the potential inside the region 0 < x < a. In this case, it is possible to have bound states since the particle can tunnel through the barrier. The exact number of bound states will depend on the specific values of A and B.

(c) For the case A < B, we need to consider the potential in the two distinct regions: x < 0 and x ≥ a.

Region x < 0:
Since the potential is infinite for x ≤ 0, the particle cannot exist in this region. Therefore, the wave function must be zero for x < 0.

Region x ≥ a:
In this region, the potential is constant and equal to B. The Schrödinger equation becomes:
-ħ²/2m * d²Ψ/dx² + BΨ = EΨ.

Solving this equation will give us the wave function Ψ and energy levels E for this region.

To discuss the boundary conditions, we need to consider the interface between the two regions. At x = a, the wave function and its derivative must be continuous, which means:

Ψ(a⁺) = Ψ(a⁻) and dΨ/dx(a⁺) = dΨ/dx(a⁻),

Here, (a⁺) represents the right-limit just after x = a, and (a⁻) represents the left-limit just before x = a.

(d) To determine if a bound state exists for the case A < B, we need to find the energy levels E that satisfy the boundary conditions described above. By solving the Schrödinger equation and applying the boundary conditions at x = a, we can determine if there exist discrete energy levels (bound states) for the given potential.

To summarize, for the case described, the possibility of bound states depends on the values of A and B in the potential. Solving the time-independent Schrödinger equation and applying the appropriate boundary conditions allows us to find the energy levels and wave functions associated with the system.