1. The efficiency of a heat engine is 43%. If 3190 J of heat is transferred from the hot resevior to the cold one, how much of that energy reaches the cold resevior?
a. 1818 J
b. 2301 J**
c. 1370 J
d. 2002 J
PLS HELP
Wrong. I know it's not C either, but I still don't know the right answer.
To calculate the amount of energy that reaches the cold reservoir, we can use the formula for the efficiency of a heat engine:
Efficiency = (Energy output / Energy input) * 100%
Given that the efficiency is 43% and the energy input is 3190 J, we can rewrite the formula as:
43% = (Energy output / 3190 J) * 100%
To find the energy output, we can rearrange the formula:
Energy output = (43% / 100%) * 3190 J
Now we can calculate the energy output:
Energy output = (0.43) * 3190 J = 1374.7 J
Therefore, the amount of energy that reaches the cold reservoir is approximately 1374.7 J. So the correct answer is c. 1370 J.
To find out how much of the energy reaches the cold reservoir, we need to use the efficiency of the heat engine. The efficiency of a heat engine is given by the formula:
Efficiency = (Energy output / Energy input) * 100
In this case, the energy input is the heat transferred from the hot reservoir, which is 3190 J, and the energy output is the amount that reaches the cold reservoir. We can rearrange the formula to solve for the energy output:
Efficiency = (Energy output / Energy input) * 100
43% = (Energy output / 3190 J) * 100
To find the energy output, we can rearrange the equation further:
Energy output = (Efficiency / 100) * Energy input
Plugging in the given values:
Energy output = (43 / 100) * 3190 J
Energy output = 0.43 * 3190 J
Energy output ≈ 1373.7 J
Therefore, the amount of energy that reaches the cold reservoir is approximately 1373.7 J. So, the correct answer is option c) 1370 J.