6g of metal M react completely with 23.66g of chlorine to form 29.66g of the metallic chloride.

Find the empirical formula of the metallic chloride.(M=27, CL=35.5)

The empirical formula of the metallic chloride is MCl2.

To find the empirical formula of the metallic chloride, we need to determine the ratio of the elements present in the compound.

Step 1: Find the amount of chlorine reacted.
From the given information, we know that 23.66g of chlorine reacted.

Step 2: Find the amount of metal M reacted.
From the given information, we know that 6g of metal M reacted.

Step 3: Calculate the moles of chlorine.
To find the moles, we divide the mass of chlorine by its molar mass.
Molar mass of chlorine (Cl) = 35.5g/mol
Moles of chlorine = Mass of chlorine / Molar mass of chlorine
Moles of chlorine = 23.66g / 35.5g/mol

Step 4: Calculate the moles of metal M.
To find the moles, we divide the mass of metal M by its molar mass.
Molar mass of metal M = 27g/mol
Moles of metal M = Mass of metal M / Molar mass of metal M
Moles of metal M = 6g / 27g/mol

Step 5: Determine the molar ratio between the elements.
Divide the moles of each element by the smallest number of moles to obtain the simplest whole number ratio.
Moles of chlorine = 23.66g / 35.5g/mol ≈ 0.67 mol
Moles of metal M = 6g / 27g/mol ≈ 0.22 mol

By dividing both moles by the smallest number of moles (0.22 mol), we get a ratio of approximately 3:1. Therefore, the empirical formula of the metallic chloride is MCl3.

To find the empirical formula of the metallic chloride, we need to determine the ratio of the elements involved in the compound.

1. Start by determining the number of moles of each element:
- Moles of metal M = mass of metal M / molar mass of metal M = 6 g / 27 g/mol = 0.222 mol
- Moles of chlorine = mass of chlorine / molar mass of chlorine = 23.66 g / 35.5 g/mol = 0.667 mol

2. Divide the number of moles of each element by the smallest number of moles to obtain the simplest mole ratio:
- Metal M: 0.222 mol / 0.222 mol = 1
- Chlorine: 0.667 mol / 0.222 mol = 3

3. The empirical formula is obtained by expressing these ratios as whole numbers:
- Metal M: 1
- Chlorine: 3

Therefore, the empirical formula of the metallic chloride is MCl₃.