Compared to wave A, wave B has a _____.
shorter wavelength and greater frequency
longer wavelength and lower frequency
shorter wavelength and lower frequency
longer wavelength and greater frequency
1. longer wavelength and greater frequency
2. amplitude
3. wave M
4. frequency
number 1 is wrong it is longer wavelength and lower frequency
weird? is 100% correct
I apologize for the mistake. You're right, wave B has a longer wavelength and lower frequency compared to wave A.
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To compare the wavelengths and frequencies of two waves, we need to understand the relationship between them. The wavelength of a wave represents the distance between two consecutive points in phase, such as two consecutive crests or troughs. The frequency of a wave represents the number of complete cycles or oscillations the wave completes in a given time.
The relationship between wavelength and frequency can be explained using the wave equation, which states that the speed of a wave is equal to the product of its wavelength and frequency. Mathematically, this can be represented as:
Speed (v) = Wavelength (λ) * Frequency (f)
From this equation, we can deduce that if the speed of the wave remains constant, an increase in wavelength will correspond to a decrease in frequency, and vice versa.
Now, let's consider the two options provided:
Option 1: Shorter wavelength and greater frequency
This statement suggests that wave B has a shorter wavelength compared to wave A, which means that the distance between consecutive points in phase of wave B is smaller than that of wave A. Additionally, it states that wave B has a greater frequency, implying that wave B completes more cycles or oscillations in a given time compared to wave A. According to the wave equation, if wave B has a shorter wavelength (smaller λ), and its speed remains the same, then it must have a greater frequency (larger f).
Option 2: Longer wavelength and lower frequency
This alternative suggests that wave B has a longer wavelength compared to wave A, meaning that the distance between consecutive points in phase of wave B is greater than that of wave A. It also states that wave B has a lower frequency, indicating that wave B completes fewer cycles or oscillations in a given time compared to wave A. Once again, considering the wave equation, if wave B has a longer wavelength (larger λ), and its speed remains constant, it implies that it must have a lower frequency (smaller f).
Therefore, based on the explanation above, the correct answer is: Wave B has a longer wavelength and lower frequency, compared to wave A.