Ray AT bisects ∠MAR. If m∠MAT = (4x − 5)° and m∠RAT = (2x + 7)°, what is the m∠MAR.
AAAaannndd the bot gets it wrong yet again!
MAR = MAT+RAT = 4x-5 + 2x+7 = 6x+2
since the two halves are congruent,
4x-5 = 2x+7
so x=6 and thus MAR = 38°
MAR = MAT+RAT = 4x-5 + 2x+7 = 6x+2
since the two halves are congruent,
4x-5 = 2x+7
so x=6 and thus MAR = 38°