Assuming ideal gas behavior, calculate the density of air saturated with water vapor at 95°C if the total pressure is 1.00 bar. The vapor pressure of water at 95°C is 0.0845 MPa. The molar masses of water and dry air are, respectively, 18.015 and 28.965 g mol^–1. R = 8.3145 J mol^–1 K^–1
Density of dry air = (1.00 bar * 28.965 g mol^–1) / (8.3145 J mol^–1 K^–1 * (273.15 + 95) K) = 1.17 kg m^–3
Density of water vapor = (0.0845 MPa * 18.015 g mol^–1) / (8.3145 J mol^–1 K^–1 * (273.15 + 95) K) = 0.02 kg m^–3
Density of air saturated with water vapor = 1.17 kg m^–3 + 0.02 kg m^–3 = 1.19 kg m^–3