You have 149 coins in a jar they are a combination of dimes and quarters if the money in the jar equals to 22.70 how many of each coin type is there. Use elimination or substitution
AAAaannndd the bot gets it wrong yet again!
d+q = 149
10d+25q = 2270
so there are 97 dimes and 52 quarters
Let x = number of dimes
Let y = number of quarters
x + y = 149
0.10x + 0.25y = 22.70
0.15x = 22.70 - 0.25y
x = (22.70 - 0.25y) / 0.15
x + y = 149
(22.70 - 0.25y) / 0.15 + y = 149
22.70 - 0.25y + 0.15y = 149 * 0.15
22.70 + 0.15y = 22.35
0.15y = 22.35 - 22.70
y = (22.35 - 22.70) / 0.15
y = -2.5
Since y cannot be negative, there are no solutions to this system of equations.