A skydiver started his jump from the airplane. He fell 4.9 m in the 1st second, 14.7 m
in the 2nd second, 24,5 m in the 3rd second. How far did he fall between the 7th and the
10th seconds?
He fell a total of 94.1 m between the 7th and 10th seconds.
To find out how far the skydiver fell between the 7th and 10th seconds, we need to first calculate the distance he fell in each of these three seconds individually and then add them together.
Given that the skydiver fell 4.9 m in the 1st second, 14.7 m in the 2nd second, and 24.5 m in the 3rd second, we can use this information to find the fall distances in the 7th, 8th, 9th, and 10th seconds.
In the first three seconds, the fall distances follow a pattern: 4.9 m, 14.7 m, and 24.5 m. This indicates that the skydiver is falling with a constant acceleration due to gravity.
To find the distance fallen in each second, we can use the equation:
d = ut + (1/2)at²
where d is the distance fallen, u is the initial velocity (in this case 0), t is the time in seconds, and a is the acceleration due to gravity, approximately 9.8 m/s².
For the 7th second:
d = 0 + (1/2)(9.8)(7²) = 240.1 m
For the 8th second:
d = 0 + (1/2)(9.8)(8²) = 313.6 m
For the 9th second:
d = 0 + (1/2)(9.8)(9²) = 441.9 m
For the 10th second:
d = 0 + (1/2)(9.8)(10²) = 490.0 m
Finally, to find the total distance fallen between the 7th and 10th seconds, we add these distances together:
Total distance = 240.1 + 313.6 + 441.9 + 490.0 = 1485.6 m
Therefore, the skydiver fell a total distance of 1485.6 meters between the 7th and 10th seconds.
To find out how far the skydiver fell between the 7th and the 10th seconds, we need to calculate the distance fallen in each of those seconds and then add them together.
The given information tells us that the skydiver fell 4.9 m in the 1st second, 14.7 m in the 2nd second, and 24.5 m in the 3rd second.
To find out the distance fallen in the 4th second, we can observe that the distances between consecutive seconds form an arithmetic sequence.
The common difference between these distances is obtained by subtracting the distance fallen in the previous second. So the common difference is:
14.7 m - 4.9 m = 9.8 m
We can continue this pattern to find the distances fallen in the 4th to 10th seconds:
4th second: 24.5 m + 9.8 m = 34.3 m
5th second: 34.3 m + 9.8 m = 44.1 m
6th second: 44.1 m + 9.8 m = 53.9 m
7th second: 53.9 m + 9.8 m = 63.7 m
8th second: 63.7 m + 9.8 m = 73.5 m
9th second: 73.5 m + 9.8 m = 83.3 m
10th second: 83.3 m + 9.8 m = 93.1 m
Now we can add up the distances fallen between the 7th and the 10th seconds:
63.7 m + 73.5 m + 83.3 m + 93.1 m = 313.6 m
Therefore, the skydiver fell a total of 313.6 meters between the 7th and the 10th seconds.