What is the length of side a given the following coordinates
A(0,0),B(3,0)C(2,10)
Side a is 3 units long.
Assuming that you are talking about triangle ABC, and we use the convention
that sides labeled a, b, and c are opposite angles A, B, and C
then
c = 3 units
a = √101 units
b = √104 units
a = sqrt (1^2 + 10^2) = sqrt(101)
b = sqrt (2*2+10^2) = sqrt(104)
c = 1
As usual I agree with I Know, not "answered"
I mean c = 3
origin to (3.0)
To find the length of side a, we need to calculate the distance between points A and B. The formula for calculating the distance between two points (x1, y1) and (x2, y2) in a coordinate system is:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, point A is (0, 0) and point B is (3, 0). Let's substitute the coordinates into the formula:
distance = √((3 - 0)^2 + (0 - 0)^2)
= √(3^2 + 0^2)
= √(9)
= 3
Therefore, the length of side a is 3 units.