Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
The distance between Milltown and Summerville is 3.5 inches on a map. If the map scale is 1 inch = 20 miles, what is the actual distance between the towns?
or, making it simpler
if 1 inch represents 20 miles,
then 3.5 represents 3.5(20) or 70 miles
70 miles
Steps:
1. Convert the map scale to a fraction: 1 inch/20 miles
2. Convert the map distance to inches: 3.5 inches
3. Multiply the map scale fraction and the map distance: (1 inch/20 miles) x (3.5 inches)
4. Simplify the fraction: 7/20
5. Convert the fraction to a decimal: 0.35
6. Multiply the decimal by the map scale: 0.35 x 20 miles
7. Simplify the product: 70 miles
thank you
To solve this problem, we can use the concept of ratio and proportion.
Given that the scale on the map is 1 inch = 20 miles, and the distance between Milltown and Summerville on the map is 3.5 inches, we need to find the actual distance between the towns.
Let's set up a proportion to find the actual distance:
1 inch on the map corresponds to 20 miles in reality.
x inches on the map correspond to the actual distance between the towns.
We can write this proportion as:
1 inch / 20 miles = 3.5 inches / x miles
To solve for x, we can cross multiply:
1 inch * x miles = 20 miles * 3.5 inches
x miles = (20 miles * 3.5 inches) / 1 inch
x miles = 70 miles
Therefore, the actual distance between Milltown and Summerville is 70 miles.