A force of 40N is applied at the end of a wire 4m long and produces an extension of 0.24mm.If the diameter of the wire is 2.0mm,calculate the (i) stress on the wire (ii) strain in the wire (2mks) Please with full solution

(i) Stress = Force/Area

Area = πr2

r = Diameter/2

Area = π(2/2)2

Area = π

Stress = 40/π

Stress = 12.7 N/mm2

(ii) Strain = Extension/Original Length

Strain = 0.24/4

Strain = 0.06 mm/m