A stone is dropped from the edge of a roof, and hits the ground with a velocity of -110 feet per second. How high (in feet) is the roof?
Note: the acceleration of an object due to earth's gravity is 32 ft/sec2
AAAaannndd the bot gets it wrong yet again!
How can it go through all those steps, only to blow the final answer?
v^2 = 2as, so
110^2 = 2*32s
s = 189 ft
The height of the roof can be calculated using the equation vf2 = vi2 + 2ad, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and d is the distance.
In this case, vf = -110 ft/sec, vi = 0 ft/sec, a = 32 ft/sec2, and d is the height of the roof.
Therefore, the height of the roof is d = (vf2 - vi2)/2a = (1102 - 02)/2(32) = 3625/64 = 56.7 feet.