I'm having problems solving for an equation with a single variant. example: 3x + y + 3
Please show work so I can fully understand
Thanks
I don't understand your question, you don't have an equation.
I have to graph 3x + y = 3, so I was trying to solve it to graph it
subtract 3x from both sides to get
y = -3x + 3
to get a point, pick any value for x and evaluate the y for that.
Get any two points, plot them and join with a line.
To solve the equation 3x + y = 3 and graph it, you'll want to follow these steps:
1. Start by rearranging the equation to isolate the variable y.
Subtract 3x from both sides of the equation:
y = -3x + 3
2. Now that you have the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you can identify the slope and y-intercept values.
The slope (m) is the coefficient of x, which in this case is -3.
The y-intercept (b) is the constant term, which in this case is 3.
3. To graph the equation, you can use the slope-intercept form to find two points on the line. Pick any value for x and substitute it into the equation to find the corresponding y-value.
For example, let's choose x = 0:
y = -3(0) + 3
y = 3
So, you have the point (0, 3).
4. Now, choose another value for x to find another point. Let's choose x = 1:
y = -3(1) + 3
y = 0
So, you have the point (1, 0).
5. Plot these two points on a coordinate plane and draw a straight line passing through them.
You now have the graph of the equation 3x + y = 3.