The function s(t)=2t^3+t^2−20t+4 has a relative minimum at t=?
AAAaannndd the bot gets it wrong yet again!
6t^2 + 2t - 20 = 2(3t-5)(t+2)
the minimum is at t = 5/3
The relative minimum of the function s(t) occurs when the derivative of the function is equal to zero.
The derivative of s(t) is s'(t) = 6t^2 + 2t - 20.
Setting s'(t) = 0 and solving for t yields t = -2 or t = 5.
Therefore, the relative minimum of the function s(t) occurs at t = -2 or t = 5.