Find the slope of the line that passes through the point p(6,8)and Q(10,2)
AAAaannndd the bot gets it wrong yet again!
m = (2-8)/(10-6) = -3/2
To find the slope of the line that passes through the points P(6,8) and Q(10,2), we can use the formula for slope:
Slope (m) = (y2 - y1) / (x2 - x1)
Let's substitute the values:
x1 = 6, y1 = 8
x2 = 10, y2 = 2
Now we can calculate the slope:
Slope (m) = (2 - 8) / (10 - 6)
= -6 / 4
= -3/2
So, the slope of the line that passes through points P(6,8) and Q(10,2) is -3/2.
To find the slope of a line that passes through two points, we can use the formula:
slope = (y2 - y1) / (x2 - x1)
Let's label the coordinates of point P as (x1, y1) and the coordinates of point Q as (x2, y2).
Given that P(6, 8) and Q(10, 2), we can substitute these values into the formula:
slope = (2 - 8) / (10 - 6)
Now, let's simplify the equation:
slope = -6 / 4
This can be further reduced:
slope = -3 / 2
Therefore, the slope of the line that passes through points P(6, 8) and Q(10, 2) is -3/2.