Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Differential Equations
Initial Value Problems
Solve the initial value problem 2x2y′′+xy′−3y= 0 wherey(1) = 1,y′(1) = 4.
1 answer
2x^2 y′′+xy′−3y= 0
y = c1 x^(3/2) + c2/x
now plug in the conditions
You can
ask a new question
or
answer this question
.
Related Questions
solve the initial value problem by separation of variables dy/dx=6x^2y and y(0)=4
1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.
2.Solve the differential equation y
solve the initial value problem by separation of variables 8. dy/dx=x+1/xy, x>0, y(1)=-4
If 25 mL of a 0.5 M NaOH solution were needed to reach the equivalence point of a 20 mL HCl solution, what was the initial
write a short story problem that can be solved in one step. Write an equation that represents the problem. Name the property
Solve the problem below using Great Circle Sailing
Initial Position, A: (11° 14’ N, 125° 03’ E) Final Position, B: (08°
My problem is multiply
4xy3 - 2x2y - 5xy2 I worked it out like this 4*2*5 =40 x*x*x= x3 x³ *y*y² =y^6 answer is 40x³ y^6 Is
how do I solve this problem 2x/2=(6-3y)/2?
2x/2=(6-3y)/2? <b>I solved it for you in my initial answer. The 2 in the numerator
y′′′−6y′′+ 11y′−6y= 0 wherey(0) =y′(0) = 0, y′′(0) = 2
Solve the following initial value problem explicitly:
y'= ye^-x , y(0)=1 How do you solve this problem? I'm really confused!
