(6) A force of 40N is applied at the end of a wire 4m long and produces an extension of 0.24mm.If the diameter of the wire is 2.0mm,calculate the (i) stress on the wire (ii) strain in the wire
(i) Stress = Force/Area = 40N/π(1mm)^2 = 12,854.95 Pa
(ii) Strain = Extension/Original Length = 0.24mm/4m = 0.00006