a micrometeor has a mass of 0.005 when it enters earth atompshere it travels at 21,000 meters per second. what its kinetic energy when it enters earths atmosphere
2,205
0.0525
1,102,500
1,102.5
1. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A baseball bat strikes a baseball.
3. 173.28J
4. Kinetic energy is transferred from the racket to the ball.
5. 1,102.5 J
(Joules)
yes in joules
To calculate the kinetic energy of the micrometeor, we can use the formula:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
Given:
Mass of the micrometeor = 0.005 kg
Velocity of the micrometeor = 21,000 m/s
Plugging in these values into the formula:
Kinetic Energy (KE) = (1/2) * 0.005 * (21,000)^2
Simplifying further:
KE = (1/2) * 0.005 * 441,000,000
KE = 0.0025 * 441,000,000
KE = 1,102,500
Therefore, the kinetic energy of the micrometeor when it enters Earth's atmosphere is 1,102,500 Joules.