A bullet of mass 0.01kg is fired with velocity of [200,0]m/s in to a sack of sand of mass 10kg which is swinging from rope. At the moment the bullet hits, the sack has a velocity of [0,0.2]m/s. Workout the velocity of bullet and sand just after the bullet hits the sack
The velocity of the bullet and the sand just after the bullet hits the sack can be calculated using the conservation of momentum.
The momentum of the bullet before the collision is 0.02 kg m/s (200 m/s x 0.01 kg).
The momentum of the sand before the collision is 2 kg m/s (10 kg x 0.2 m/s).
The total momentum before the collision is 2.02 kg m/s.
After the collision, the momentum of the bullet and the sand will be the same as the total momentum before the collision.
Therefore, the velocity of the bullet and the sand just after the bullet hits the sack is 2.02 kg m/s divided by the combined mass of the bullet and the sand, which is 10.01 kg.
This gives a velocity of 0.2 kg m/s for the bullet and the sand just after the bullet hits the sack.