An impulse of 30. 0 newton-seconds is applied to a 5. 00-kilogram mass. If the mass had a speed of 100. Meters per second before the impulse, its speed after the impulse could be.
The speed after the impulse would be 130 meters per second.
To find the speed of the mass after the impulse, we can use the principle of conservation of momentum. The impulse is equal to the change in momentum. The momentum of an object is given by the product of its mass and velocity.
Given:
Impulse (J) = 30.0 N⋅s (newton-seconds)
Mass (m) = 5.00 kg
Initial velocity (u) = 100 m/s
Let the final velocity be represented as v.
The equation for impulse is:
J = m * (v - u)
Substituting the given values:
30.0 N⋅s = 5.00 kg * (v - 100 m/s)
Now, let's solve for v:
30.0 N⋅s = 5.00 kg * v - 5.00 kg * 100 m/s
30.0 N⋅s + 500.0 kg⋅m/s = 5.00 kg * v
v = (30.0 N⋅s + 500.0 kg⋅m/s) / 5.00 kg
v = (30.0 N⋅s) / 5.00 kg + (500.0 kg⋅m/s) / 5.00 kg
v = 6.00 m/s + 100.0 m/s
v = 106.0 m/s
Therefore, the speed of the mass after the impulse could be 106.0 meters per second.