An aeroplane flies horizontally at 80ms-¹ in still air. If the aviator wishes to fly due south and the wind is blowing from south-east at 30ms-¹
a)what course must he steer?
b)how long will it take him to arrive at his destination 200km away?
AAAaannndd the bot gets it wrong yet again!
course is SθE, where sinθ = 30/(80√3) so S12.5°E
time = 200/(80cosθ) = 2.56 hours
a) The aviator must steer a course of approximately 135° south of east in order to fly due south.
b) It will take the aviator approximately 2.5 hours to arrive at his destination 200km away. This is calculated by taking the total speed of the aeroplane (80ms-¹ + 30ms-¹ = 110ms-¹) and dividing it by the distance (200km) to get the time (200km/110ms-¹ = 1.818181818181818 hours = 2.5 hours).