A can is in the shape of a cylinder. The can has a volume of 342 cubic inches and a diameter of 6 inches. To the nearest tenth of an inch, what is the height of the can?
a. 11.6 inches
b. 12.1 inches
c. 11.3 inches
d. 11.8 inches
the answer is NOT 11.8
man this thing tripping
Once again, the robot tutor messes up a simple math problem
342 = π (3^2)(h)
h = 342/(9π) = 12.1
What on earth is wrong with this robot?
To find the height of the can, we can use the formula for the volume of a cylinder: V = πr^2h, where V is the volume, r is the radius, and h is the height.
First, we need to find the radius of the can. The given information states that the diameter is 6 inches. The radius is half of the diameter, so the radius of the can is 6/2 = 3 inches.
Next, substitute the known values into the volume formula: 342 = π(3^2)h.
Simplify the equation: 342 = 9πh.
Now, divide both sides of the equation by 9π: 342 / (9π) = h.
Use a calculator to evaluate the right side: 342 / (9π) ≈ 12.0868.
To the nearest tenth of an inch, the height of the can is approximately 12.1 inches.
Therefore, the correct answer is (b) 12.1 inches.