A car traveling initially at 5.47 m/s accelerates at the rate of 1.65 m/s/s for a time of 9.06 s. What is its velocity at the end of the acceleration?
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To find the final velocity of the car at the end of the acceleration, you can use the formula:
Final velocity (v) = Initial velocity (u) + (acceleration (a) × time (t))
Given:
Initial velocity (u) = 5.47 m/s
Acceleration (a) = 1.65 m/s²
Time (t) = 9.06 s
Plugging in the values into the formula:
v = 5.47 m/s + (1.65 m/s² × 9.06 s)
v = 5.47 m/s + 15.009 m/s
v = 20.48 m/s
Therefore, the velocity of the car at the end of the acceleration is 20.48 m/s.
To find the final velocity of the car, we can use the equation of motion:
v = u + at
In this equation,
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.
Given:
Initial velocity, u = 5.47 m/s
Acceleration, a = 1.65 m/s²
Time, t = 9.06 s
Now, substitute the given values into the equation:
v = 5.47 m/s + (1.65 m/s²)(9.06 s)
Simplifying the equation:
v = 5.47 m/s + 14.949 m/s
v = 20.419 m/s
Therefore, the velocity of the car at the end of the acceleration is 20.419 m/s.