A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground then find how long will it take between when the stone was thrown and when it comes back to the ground?
The time taken for the stone to come back to the ground can be calculated using the equation:
t = 2v sin(θ) / g
where v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity (9.8 m/s2).
Therefore, the time taken for the stone to come back to the ground is:
t = 2(25 m/s) sin(30°) / 9.8 m/s2
t = 5.1 s