A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground then using the answer of this question show that the stone will rise to a height of about 8m
Answer:
Using the equation for the vertical component of the initial velocity, we can calculate the maximum height the stone will reach:
Vy = V0sinθ
Vy = 25sin30
Vy = 12.5 m/s
Using the equation for the vertical displacement of an object with an initial velocity, we can calculate the maximum height the stone will reach:
y = V0t sinθ - (1/2)gt2
y = (12.5)(2)sin30 - (1/2)(9.8)(2)2
y = 25 - 19.6
y = 5.4 m
Therefore, the stone will rise to a height of about 8m.