A 54.0 kg diver steps off a diving board and drops straight down into the water. The water provides an upward average net force of 1350 N. If the diver comes to rest 4.9 m below the water's surface, what is the total distance between the diving board and the diver's stopping point underwater?
__________m
At the top of the board, the diver has PE = mgh
At the bottom, he has KE = (1/2)*m*v^2 = mgh
It takes a 1500 N force 5 meters to decelerate a 50 kg mass traveling at v
So, you can find the initial velocity
Which also means you can find the KE
Make KE equal to the PE, and solve for h and add 5
All of that and you get 20.3 m