The average score of all golfers for a particular course has a mean of 60 and a standard deviation of 4 suppose 64 golfers played the course today find the probability that the average score of the 64 golfers exceeded 61
The probability that the average score of the 64 golfers exceeded 61 is 0.8413. This can be calculated using the z-score formula:
z = (61 - 60) / (4 / √64)
z = 0.25
The probability of a z-score of 0.25 is 0.8413.