Marbles come in two sizes: 1-inch diameter and 2-inch diameter. The 1-inch diameter marbles cost 30 cents less than the 2-inch marbles. Rochelle buys 25 1-inch marbles for her science project and spends exactly $10. Find the cost of a 2-inch marble.
Wrong again!!!
The answer doesn't even sound logical
cost of 1-inch marble --- x
she buys 25 of those for $10
cost of each 1-inch marble = 10/25 = .4
so each costs 40 cents.
since the 2-incher costs 30 cents more, it must cost 70 cents each
To find the cost of a 2-inch marble, let's assign variables:
Let's say the cost of a 2-inch marble is x cents.
According to the given information, the cost of a 1-inch marble is 30 cents less than the cost of a 2-inch marble. So, the cost of a 1-inch marble would be (x - 30) cents.
We also know that Rochelle bought 25 marble which cost her exactly $10, which is equal to 1000 cents.
Now, we can set up the equation:
25 * (x - 30) = 1000
Let's solve for x:
25x - 750 = 1000
Add 750 to both sides:
25x = 1750
Divide both sides by 25:
x = 70
Therefore, the cost of a 2-inch marble is 70 cents.
To find the cost of a 2-inch marble, we can first deduce the cost of a 1-inch marble.
Let's assume that the cost of a 2-inch marble is x cents. According to the given information, the cost of a 1-inch marble is 30 cents less than the cost of a 2-inch marble. Therefore, the cost of a 1-inch marble can be expressed as (x - 30) cents.
Rochelle buys 25 1-inch marbles for her science project and spends exactly $10. We can translate this information into an equation:
25 * (x - 30) = 1000
To solve for x, let's simplify the equation:
25x - 750 = 1000
Add 750 to both sides:
25x = 1750
Now, divide both sides by 25:
x = 70
So, the cost of a 2-inch marble is 70 cents.