When 496 5 grams of Pb(NO3)2 reacts completely with KBr, how much will the

Question

total mass of the products be? Explain your answer
Mass mass problem - mass of reactant to mass of product

Answer 1

The total mass of the products will be 896 grams. This is because the molar mass of Pb(NO3)2 is 331.2 g/mol and the molar mass of KBr is 119.0 g/mol. Therefore, 496.5 g of Pb(NO3)2 will react with 496.5 g/331.2 = 1.50 mol of Pb(NO3)2 and 1.50 mol of KBr will produce 1.50 mol of PbBr2 and 1.50 mol of KNO3. The molar mass of PbBr2 is 368.2 g/mol and the molar mass of KNO3 is 101.1 g/mol. Therefore, 1.50 mol of PbBr2 will produce 1.50 x 368.2 = 552.3 g and 1.50 mol of KNO3 will produce 1.50 x 101.1 = 151.7 g. The total mass of the products will be 552.3 g + 151.7 g = 803.0 g.