Find all side lengths to the nearest tenth and all angle measures to the nearest degree.
a= 0.12
b= 1.9
c= 1.7
Angle A= 90°
Angle B= 53°
Angle C= 37°
I doubt it !
Wrong again!
If there is a 90° angle, then
1.9^2 = 1.7*2 + .12^2
3.61 = 2.89 + .0144
3.61= 2.9044 ????
Let's find the largest angle, which would be opposite the largest side
1.9^2 = 1.7^2 + .12^2 - 2(1.7)(.12)cosA
cosA = -.7056/.408 = -1.729 , but -1 ≤ cosA ≤ 1
so the triangle is not even possible since
1.7 + .12 < 1.9
Did the automated robot tutor ever screw this one up !!!!