Let f (x) = cos x and g(x) = sin x. Find the center of gravity (x, y) of the region between the graphs of f and g on [0, ๐œ‹/2].

(x, y)=

nope

x = y = 4r/3ฯ€ =

so it's (4/(3ฯ€) , 4/(3ฯ€))

CLEARLY not at (ฯ€/2,0) which lies on the x-axis, and isn't even inside the circle!

To find the center of gravity (x, y) of the region between the graphs of f(x) = cos(x) and g(x) = sin(x) on the interval [0, ๐œ‹/2], we need to calculate the average x-coordinate and the average y-coordinate of the region.

The center of gravity can be calculated using the following formulas:

Average x-coordinate (xฬ„) = (1/A) * โˆซ[a,b] x * f(x) dx
Average y-coordinate (yฬ„) = (1/A) * โˆซ[a,b] ฦ’(x) dx

where A is the area of the region, and [a, b] is the interval of interest.

In this case, the interval of interest is [0, ๐œ‹/2], and we want to find the average x and y coordinates of the region between the graphs of f(x) = cos(x) and g(x) = sin(x) within that interval.

Let's calculate:

1. Area of the region (A):
To find the area of the region between the graphs, we need to calculate the difference between the integrals of the two functions over the interval [0, ๐œ‹/2].
A = โˆซ[0, ๐œ‹/2] (f(x) - g(x)) dx

= โˆซ[0, ๐œ‹/2] (cos(x) - sin(x)) dx

2. Average x-coordinate (xฬ„):
To find the average x-coordinate, we need to calculate the integral of x * (f(x) - g(x)) over the interval [0, ๐œ‹/2].
xฬ„ = (1/A) * โˆซ[0, ๐œ‹/2] (x * (cos(x) - sin(x))) dx

3. Average y-coordinate (yฬ„):
To find the average y-coordinate, we need to calculate the integral of (f(x) - g(x)) over the interval [0, ๐œ‹/2].
yฬ„ = (1/A) * โˆซ[0, ๐œ‹/2] (cos(x) - sin(x)) dx

Now we can use these formulas to calculate the values (x, y) for the center of gravity.

(1.5707963267949, 0)