In triangle ABC a=0.12, b=1.9, c=1.7. Solve the triangle.
The angles of the triangle can be found using the Law of Cosines:
A = cos^-1((b^2 + c^2 - a^2)/(2bc)) = cos^-1(3.5361/3.48) = 87.2°
B = cos^-1((a^2 + c^2 - b^2)/(2ac)) = cos^-1(0.0081/0.216) = 1.2°
C = 180° - (A + B) = 180° - (87.2° + 1.2°) = 91.6°